"VELOCITY and ACCELERATION versus TIME in a STRAIGHT LINE. An object has an initial velocity VELINIT and is accelerated at a constant rate ACCELER to average velocity VELOAVE and travels DISTANCE in TIME. ------------- ACCELER │ OBJECT │ ----> straight line │ │ VELOCITY -----------> ------------- ----> | .......>.....>.......>.....| 0 TIME Use these equations when acceleration, velocity and time are important factors. A=accleration, V=final velocity at time T, S=distance traveled at time T. Enter at least two variables with nonzero values. For constant velocity, V=VELINIT. (c) Copyright PCSCC, Inc., 1993 *** Answer to problem *** Must use consistent units such as ft/s. Type ?, then (esc) 0 (enter) to set all variables to zero. Set T to 10. Set V to the velocity in ft/s by moving cursor to V and typing 30*5280/3600. This chain multiplication results in a velocity of44 ft/s. Note: VELINIT=0 since the cat starts from rest. (a) ACCELER=4.4 ft/s and (b) DISTANCE=220 ft. Type any key to exit. ||A cheetah can reach a speed of 30 mi/hr starting from rest in 10s. (a) What is its acceleration? (b) how far has it gone in the 10 s? Type comma key to see answer. Type (F2) to return to helpfile."
