"VELOCITY and ACCELERATION versus DISTANCE in a STRAIGHT LINE. An object has an initial velocity VELINIT and is accelerated at a constant rate ACCELER to average velocity VELOAVE and travels DISTANCE in TIME. ------------- ACCELER │ OBJECT │ ----> straight line │ │ VELOCITY -----------> ------------- ----> | .......>.....>.......>.....| 0 DISTANCE Use these equations when acceleration, velocity and distance are important factors. A=accleration, V=final velocity at distance S, S=distance traveled at TIME. Enter at least two variables with nonzero values. For constant velocity, V=VELINIT. Type any key to exit. (c) Copyright PCSCC, Inc., 1993 *** Answer to problem *** Assume that the car and man may collide. Type ? then (esc) 0 (enter) to set allvariables to zero. Set A to 16. Set S to 100. (a) The impact time is 3.5 s and (b) the impact VELOCITY is 56.5 ft/s. Type any key to exit. ||While parked on a steep hill, a car's emergency brake fails andit accelerates at 16 ft/s^2 downhill. (a) How much time does the man, 100 ft downhill, have to get out of its way? (b) At what velocity will it hit him? Type comma key to see answer. Type (F2) to return to helpfile."
