"SPHERICAL REFRACTING MIRRORS, IMAGE vs MAGNIFICATION. A diagram of the Problem is shown below. Mirror is represented by 's'. s · o· S = source object · ° s ° V = vertex of sphere · ° s ° P C P = image (between F and C) S ·°· · · · · · · · ·o· · ·°o · · o R = 2 * F | V|s | ·° | | s ·|° R S[O] = distance S to vertex | | s° | S[I] = distance vertex to image |-------S[O]---------|-S[I]-| C = center of sphere R = radius curvat. (c) Copyright PCSCC, Inc., 1993 Sign Convention: S[O] + means its left of vertex V focus + means concave S[I] + means its left of vertex V focus - means convex R + means center C is right of V *** Answer(s) to problem *** Solve for FOCUS (focal length) by approximation. Set R=10 (a guess). Set S[I]=0 and S[O]=150. Move cursor to R. Type S. For variable, type (end esc) FOCUS (enter). For value, type 400 (enter) and for range, use default, type (enter). R=-800 ( C is left of V, concave) and S[I]=-240 to right of V, virtual, erect and magnified. ||An eraser 5 cm tall sits 150 cm in front of a concave mirror offocal length 400 cm. (a) Describe the image. Type comma key to see answer. Type (F2) to return to application file."
