home *** CD-ROM | disk | FTP | other *** search
/ PC World Komputer 1997 February / PCWK0297.iso / technika / formcalc / optics / optc421.equ < prev    next >
Text File  |  1994-07-20  |  2KB  |  17 lines

  1. "AST3CAL3 EQUATION VARIABLE","07-20-1994","20:54:40"
  2. "FOCAL_LENGTH=F+(1-SIGN(ABS(F)))*SQR(ABS(X[I]*X[O])) TRANSVERSE_MAGNIFICATION=-IMAGE_TO_F_DISTANCE/NZE(FOCAL_LENGTH) IMAGE_DISTANCE_TO_LENS=FOCAL_LENGTH+IMAGE_TO_F_DISSTANCE OBJECT_DISTANCE_TO_LENSE=FOCAL_LENGTH+OBJECT_TO_F_DISTANCE"
  3. "THIN LENS IMAGERY, CHARACTERISTICS for REAL OBJECTS, NEWTONIAN.A summary of object/image properties for concave and convex lenses follows.          (Enter 2 of 3 values and leave unknown as 0, program will calculate.)      Lens   OBJECT         <-------------------- IMAGE ------------------->                 Location       Type       Location         Orient.   rel. size                                                                                           CNCV   anywhere       virtual    |S[I]<|F|        erect     minfied                                                                                             CNVX   ∞>S[O]>2*F     real       F<S[I]<2*F       invert.   minified            CNVX   S[O]=2*F       real       S[I]=2*F         invert.   same size           CNVX   F<S[O]<2*F     real       ∞>S[I]>2*f       invert.   magnified           CNVX   S[O]=F                      ±∞                                           CNVX   S[O]<F         virtual    |S[I]|>S[O]      erect     magnified                 F = focal length    X[O or I] => distance from F to object or image.             Transverse magnification: M[T] < 0 inverted |M[T]| < 1 minified          *** Answer(s) to problem ***                              (c) PCSCC, Inc., 1993 This problem is solved by approximation. Image height is not required. Set F=30,X[I]=1 and X[O]=0. Move cursor to X[I], type S and type (end esc) OBJECT_DIST   (enter). For value type (end esc) 100 (enter). Use default for range, type      (enter). Trans_mag=-.43, image at 43.9. Mo is inverted and minified, too!                      ||A 9 cm tall statue of Mo Howard is sitting 100 cm from a       positive (converging) lens of 30 cm focal length. (a) Describe Mo's image.           Type comma key to see answer. Type (F2) to return to application file."
  4. 9
  5. 30,0,""
  6. -.4285714285714283,0,""
  7. 42.85714285714285,0,""
  8. 100,0,""
  9. 30,0,""
  10. 12.85714285714285,0,""
  11. 0,0,""
  12. 12.85714285714285,0,""
  13. 70.00000000000004,0,""
  14. 1
  15. 0
  16. 0
  17.