"SPHERICAL REFRACTING SURFACES, OBJECT FOCAL LENGTH. A diagram of the Problem is shown below. Surface is represented by 's'. s A · o· · · · · >∞ F = object focus N[1] = index L[O] · s · L[I] V = vertex of sphere outside F . s R· P = image at ∞ N[2] = index ·· · · · · · ·o· · · o L[O] = distance F to sphere inside V|s C L[I] = ∞ N[1] | s N[2] F[O] = distance S to vertex | s F[I] = ∞ |----F[O]------|------F[I]---->∞ C = center of sphere R = radius curvat. (c) Copyright PCSCC, Inc., 1993 Sign Convention: F[O] + means its left of vertex V F[I] = ∞ is always to right of vertex V R + means center C is right of V *** Answer(s) to problem *** Variables are set to proper values at entry. Note, value of unknown should be set to 0.0. Enter any 3 of 4 knowns, program calculates missing (=0) one. F[O] = 13.6. Image is real and to right of V. Type any key to exit. ||An interface separates air on the left and glass (Ng=1.44) on the right. (a) What is the object focal length if its radius of curvature is 6 cm? Type comma key to see answer. Type (F2) to return to application file."
