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- SUBROUTINE SSIFA(A,LDA,N,KPVT,INFO)
- INTEGER LDA,N,KPVT(1),INFO
- REAL A(LDA,1)
- C
- C SSIFA FACTORS A REAL SYMMETRIC MATRIX BY ELIMINATION
- C WITH SYMMETRIC PIVOTING.
- C
- C TO SOLVE A*X = B , FOLLOW SSIFA BY SSISL.
- C TO COMPUTE INVERSE(A)*C , FOLLOW SSIFA BY SSISL.
- C TO COMPUTE DETERMINANT(A) , FOLLOW SSIFA BY SSIDI.
- C TO COMPUTE INERTIA(A) , FOLLOW SSIFA BY SSIDI.
- C TO COMPUTE INVERSE(A) , FOLLOW SSIFA BY SSIDI.
- C
- C ON ENTRY
- C
- C A REAL(LDA,N)
- C THE SYMMETRIC MATRIX TO BE FACTORED.
- C ONLY THE DIAGONAL AND UPPER TRIANGLE ARE USED.
- C
- C LDA INTEGER
- C THE LEADING DIMENSION OF THE ARRAY A .
- C
- C N INTEGER
- C THE ORDER OF THE MATRIX A .
- C
- C ON RETURN
- C
- C A A BLOCK DIAGONAL MATRIX AND THE MULTIPLIERS WHICH
- C WERE USED TO OBTAIN IT.
- C THE FACTORIZATION CAN BE WRITTEN A = U*D*TRANS(U)
- C WHERE U IS A PRODUCT OF PERMUTATION AND UNIT
- C UPPER TRIANGULAR MATRICES , TRANS(U) IS THE
- C TRANSPOSE OF U , AND D IS BLOCK DIAGONAL
- C WITH 1 BY 1 AND 2 BY 2 BLOCKS.
- C
- C KPVT INTEGER(N)
- C AN INTEGER VECTOR OF PIVOT INDICES.
- C
- C INFO INTEGER
- C = 0 NORMAL VALUE.
- C = K IF THE K-TH PIVOT BLOCK IS SINGULAR. THIS IS
- C NOT AN ERROR CONDITION FOR THIS SUBROUTINE,
- C BUT IT DOES INDICATE THAT SSISL OR SSIDI MAY
- C DIVIDE BY ZERO IF CALLED.
- C
- C LINPACK. THIS VERSION DATED 08/14/78 .
- C JAMES BUNCH, UNIV. CALIF. SAN DIEGO, ARGONNE NAT. LAB.
- C
- C SUBROUTINES AND FUNCTIONS
- C
- C BLAS SAXPY,SSWAP,ISAMAX
- C FORTRAN ABS,AMAX1,SQRT
- C
- C INTERNAL VARIABLES
- C
- REAL AK,AKM1,BK,BKM1,DENOM,MULK,MULKM1,T
- REAL ABSAKK,ALPHA,COLMAX,ROWMAX
- INTEGER IMAX,IMAXP1,J,JJ,JMAX,K,KM1,KM2,KSTEP,ISAMAX
- LOGICAL SWAP
- C
- C
- C INITIALIZE
- C
- C ALPHA IS USED IN CHOOSING PIVOT BLOCK SIZE.
- ALPHA = (1.0E0 + SQRT(17.0E0))/8.0E0
- C
- INFO = 0
- C
- C MAIN LOOP ON K, WHICH GOES FROM N TO 1.
- C
- K = N
- 10 CONTINUE
- C
- C LEAVE THE LOOP IF K=0 OR K=1.
- C
- C ...EXIT
- IF (K .EQ. 0) GO TO 200
- IF (K .GT. 1) GO TO 20
- KPVT(1) = 1
- IF (A(1,1) .EQ. 0.0E0) INFO = 1
- C ......EXIT
- GO TO 200
- 20 CONTINUE
- C
- C THIS SECTION OF CODE DETERMINES THE KIND OF
- C ELIMINATION TO BE PERFORMED. WHEN IT IS COMPLETED,
- C KSTEP WILL BE SET TO THE SIZE OF THE PIVOT BLOCK, AND
- C SWAP WILL BE SET TO .TRUE. IF AN INTERCHANGE IS
- C REQUIRED.
- C
- KM1 = K - 1
- ABSAKK = ABS(A(K,K))
- C
- C DETERMINE THE LARGEST OFF-DIAGONAL ELEMENT IN
- C COLUMN K.
- C
- IMAX = ISAMAX(K-1,A(1,K),1)
- COLMAX = ABS(A(IMAX,K))
- IF (ABSAKK .LT. ALPHA*COLMAX) GO TO 30
- KSTEP = 1
- SWAP = .FALSE.
- GO TO 90
- 30 CONTINUE
- C
- C DETERMINE THE LARGEST OFF-DIAGONAL ELEMENT IN
- C ROW IMAX.
- C
- ROWMAX = 0.0E0
- IMAXP1 = IMAX + 1
- DO 40 J = IMAXP1, K
- ROWMAX = AMAX1(ROWMAX,ABS(A(IMAX,J)))
- 40 CONTINUE
- IF (IMAX .EQ. 1) GO TO 50
- JMAX = ISAMAX(IMAX-1,A(1,IMAX),1)
- ROWMAX = AMAX1(ROWMAX,ABS(A(JMAX,IMAX)))
- 50 CONTINUE
- IF (ABS(A(IMAX,IMAX)) .LT. ALPHA*ROWMAX) GO TO 60
- KSTEP = 1
- SWAP = .TRUE.
- GO TO 80
- 60 CONTINUE
- IF (ABSAKK .LT. ALPHA*COLMAX*(COLMAX/ROWMAX)) GO TO 70
- KSTEP = 1
- SWAP = .FALSE.
- GO TO 80
- 70 CONTINUE
- KSTEP = 2
- SWAP = IMAX .NE. KM1
- 80 CONTINUE
- 90 CONTINUE
- IF (AMAX1(ABSAKK,COLMAX) .NE. 0.0E0) GO TO 100
- C
- C COLUMN K IS ZERO. SET INFO AND ITERATE THE LOOP.
- C
- KPVT(K) = K
- INFO = K
- GO TO 190
- 100 CONTINUE
- IF (KSTEP .EQ. 2) GO TO 140
- C
- C 1 X 1 PIVOT BLOCK.
- C
- IF (.NOT.SWAP) GO TO 120
- C
- C PERFORM AN INTERCHANGE.
- C
- CALL SSWAP(IMAX,A(1,IMAX),1,A(1,K),1)
- DO 110 JJ = IMAX, K
- J = K + IMAX - JJ
- T = A(J,K)
- A(J,K) = A(IMAX,J)
- A(IMAX,J) = T
- 110 CONTINUE
- 120 CONTINUE
- C
- C PERFORM THE ELIMINATION.
- C
- DO 130 JJ = 1, KM1
- J = K - JJ
- MULK = -A(J,K)/A(K,K)
- T = MULK
- CALL SAXPY(J,T,A(1,K),1,A(1,J),1)
- A(J,K) = MULK
- 130 CONTINUE
- C
- C SET THE PIVOT ARRAY.
- C
- KPVT(K) = K
- IF (SWAP) KPVT(K) = IMAX
- GO TO 190
- 140 CONTINUE
- C
- C 2 X 2 PIVOT BLOCK.
- C
- IF (.NOT.SWAP) GO TO 160
- C
- C PERFORM AN INTERCHANGE.
- C
- CALL SSWAP(IMAX,A(1,IMAX),1,A(1,K-1),1)
- DO 150 JJ = IMAX, KM1
- J = KM1 + IMAX - JJ
- T = A(J,K-1)
- A(J,K-1) = A(IMAX,J)
- A(IMAX,J) = T
- 150 CONTINUE
- T = A(K-1,K)
- A(K-1,K) = A(IMAX,K)
- A(IMAX,K) = T
- 160 CONTINUE
- C
- C PERFORM THE ELIMINATION.
- C
- KM2 = K - 2
- IF (KM2 .EQ. 0) GO TO 180
- AK = A(K,K)/A(K-1,K)
- AKM1 = A(K-1,K-1)/A(K-1,K)
- DENOM = 1.0E0 - AK*AKM1
- DO 170 JJ = 1, KM2
- J = KM1 - JJ
- BK = A(J,K)/A(K-1,K)
- BKM1 = A(J,K-1)/A(K-1,K)
- MULK = (AKM1*BK - BKM1)/DENOM
- MULKM1 = (AK*BKM1 - BK)/DENOM
- T = MULK
- CALL SAXPY(J,T,A(1,K),1,A(1,J),1)
- T = MULKM1
- CALL SAXPY(J,T,A(1,K-1),1,A(1,J),1)
- A(J,K) = MULK
- A(J,K-1) = MULKM1
- 170 CONTINUE
- 180 CONTINUE
- C
- C SET THE PIVOT ARRAY.
- C
- KPVT(K) = 1 - K
- IF (SWAP) KPVT(K) = -IMAX
- KPVT(K-1) = KPVT(K)
- 190 CONTINUE
- K = K - KSTEP
- GO TO 10
- 200 CONTINUE
- RETURN
- END