home *** CD-ROM | disk | FTP | other *** search
- SUBROUTINE SGEDI(A,LDA,N,IPVT,DET,WORK,JOB)
- INTEGER LDA,N,IPVT(1),JOB
- REAL A(LDA,1),DET(2),WORK(1)
- C
- C SGEDI COMPUTES THE DETERMINANT AND INVERSE OF A MATRIX
- C USING THE FACTORS COMPUTED BY SGECO OR SGEFA.
- C
- C ON ENTRY
- C
- C A REAL(LDA, N)
- C THE OUTPUT FROM SGECO OR SGEFA.
- C
- C LDA INTEGER
- C THE LEADING DIMENSION OF THE ARRAY A .
- C
- C N INTEGER
- C THE ORDER OF THE MATRIX A .
- C
- C IPVT INTEGER(N)
- C THE PIVOT VECTOR FROM SGECO OR SGEFA.
- C
- C WORK REAL(N)
- C WORK VECTOR. CONTENTS DESTROYED.
- C
- C JOB INTEGER
- C = 11 BOTH DETERMINANT AND INVERSE.
- C = 01 INVERSE ONLY.
- C = 10 DETERMINANT ONLY.
- C
- C ON RETURN
- C
- C A INVERSE OF ORIGINAL MATRIX IF REQUESTED.
- C OTHERWISE UNCHANGED.
- C
- C DET REAL(2)
- C DETERMINANT OF ORIGINAL MATRIX IF REQUESTED.
- C OTHERWISE NOT REFERENCED.
- C DETERMINANT = DET(1) * 10.0**DET(2)
- C WITH 1.0 .LE. ABS(DET(1)) .LT. 10.0
- C OR DET(1) .EQ. 0.0 .
- C
- C ERROR CONDITION
- C
- C A DIVISION BY ZERO WILL OCCUR IF THE INPUT FACTOR CONTAINS
- C A ZERO ON THE DIAGONAL AND THE INVERSE IS REQUESTED.
- C IT WILL NOT OCCUR IF THE SUBROUTINES ARE CALLED CORRECTLY
- C AND IF SGECO HAS SET RCOND .GT. 0.0 OR SGEFA HAS SET
- C INFO .EQ. 0 .
- C
- C LINPACK. THIS VERSION DATED 08/14/78 .
- C CLEVE MOLER, UNIVERSITY OF NEW MEXICO, ARGONNE NATIONAL LAB.
- C
- C SUBROUTINES AND FUNCTIONS
- C
- C BLAS SAXPY,SSCAL,SSWAP
- C FORTRAN ABS,MOD
- C
- C INTERNAL VARIABLES
- C
- REAL T
- REAL TEN
- INTEGER I,J,K,KB,KP1,L,NM1
- C
- C
- C COMPUTE DETERMINANT
- C
- IF (JOB/10 .EQ. 0) GO TO 70
- DET(1) = 1.0E0
- DET(2) = 0.0E0
- TEN = 10.0E0
- DO 50 I = 1, N
- IF (IPVT(I) .NE. I) DET(1) = -DET(1)
- DET(1) = A(I,I)*DET(1)
- C ...EXIT
- IF (DET(1) .EQ. 0.0E0) GO TO 60
- 10 IF (ABS(DET(1)) .GE. 1.0E0) GO TO 20
- DET(1) = TEN*DET(1)
- DET(2) = DET(2) - 1.0E0
- GO TO 10
- 20 CONTINUE
- 30 IF (ABS(DET(1)) .LT. TEN) GO TO 40
- DET(1) = DET(1)/TEN
- DET(2) = DET(2) + 1.0E0
- GO TO 30
- 40 CONTINUE
- 50 CONTINUE
- 60 CONTINUE
- 70 CONTINUE
- C
- C COMPUTE INVERSE(U)
- C
- IF (MOD(JOB,10) .EQ. 0) GO TO 150
- DO 100 K = 1, N
- A(K,K) = 1.0E0/A(K,K)
- T = -A(K,K)
- CALL SSCAL(K-1,T,A(1,K),1)
- KP1 = K + 1
- IF (N .LT. KP1) GO TO 90
- DO 80 J = KP1, N
- T = A(K,J)
- A(K,J) = 0.0E0
- CALL SAXPY(K,T,A(1,K),1,A(1,J),1)
- 80 CONTINUE
- 90 CONTINUE
- 100 CONTINUE
- C
- C FORM INVERSE(U)*INVERSE(L)
- C
- NM1 = N - 1
- IF (NM1 .LT. 1) GO TO 140
- DO 130 KB = 1, NM1
- K = N - KB
- KP1 = K + 1
- DO 110 I = KP1, N
- WORK(I) = A(I,K)
- A(I,K) = 0.0E0
- 110 CONTINUE
- DO 120 J = KP1, N
- T = WORK(J)
- CALL SAXPY(N,T,A(1,J),1,A(1,K),1)
- 120 CONTINUE
- L = IPVT(K)
- IF (L .NE. K) CALL SSWAP(N,A(1,K),1,A(1,L),1)
- 130 CONTINUE
- 140 CONTINUE
- 150 CONTINUE
- RETURN
- END