Since is given as , must be 3A. Since is given as , must be 4.5A from equation (6). Using equation (5), can be found to be 1.5A. Since the total current is given as 12A and is the only remaining unknown current, must equal 7.5A. Using equation (3), is then found to be . At this point, the only unknown is . Equation (1) yields the value of for . In sum, the currents and resistances are given by:
