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- 187
- à 9.1è Evaluating Variable Expressions
-
- äïPlease evaluate the following Variable Expressions at the
- given specified values of the variable.
-
- #âèEvaluateï5∙(2x - yì)ïby replacing x with "2" and y with "3".
-
- #ê 5∙(2x - yì)ï=ï5∙(2∙2 - 3ì)ï=ï5∙(2∙2 - 9)ï=ï5∙(4 - 9)
-
- êêê5∙(4 + (-9))ï=ï5∙(-5)ï=ï-25
-
- #Thus, the value of 5∙(2x - yì) when x is "2" and y is "3" is -25.
-
- #éSèIn order to evaluate the Variable Expression, 5∙(2x - yì) ,
- when x is "2" and y is "3", it is necessary to substitute "2" in place
- of x and "3" in place of y.
- #êêêêï5∙(2x - yì)
- #êêêë =ï5∙(2∙2 - 3ì)
-
- After the substitution, you should simplify using the correct order of
- operations and the rules for operations on signed numbers that were
- given in the last chapter.ïFirst, clear the exponent inside the paren-
- çs.êêêï5∙(2∙2 - 9)
-
- Then, perform the multiplication inside the parençs.
- êêêêï5∙(4 - 9)
-
- This is followed by the subtraction inside the parençs.
- êêêêè5∙(4 + (-9)
- êêêê=ï5∙(-5)
-
- Finally, the last multiplication is performed.
- êêêêè-25
-
- #Thus, the value of the Variable Expression, 5∙(2x - yì), when x is "2"
- and y is "3" is -25.
- 1
- #êëEvaluateïxì + 5yìïif x is "-3" and y is "-4".
-
-
- êïA)ï36ê B)ï54êïC)ï89êïD)ïå
-
-
- ü
- #êêêêë xì + 5yì
- #êêêê=ï(-3)ì + 5(-4)ì
- êêêê=ë9 + 5∙16
- êêêê=ë9 + 80
- êêêê=ë 89
-
- ÇïC
- 2
- êëEvaluateï3x - 5yïif x is "4" and y is "3".
-
-
- êïA)ï-3ê B)ï5êèC)ï6êèD)ïå
-
-
- ü
- êêêêë3x - 5y
- êêêê=è3(4) - 5(3)
- êêêê=è 12 - 15
- êêêê=è12 + (-15)
- êêêê=ë -3
-
- ÇïA
- 3
- êèEvaluateïa∙(3b + c) if a is "5", b is "-4", and c is "-5".
-
-
- êïA)ï-55êB)ï-85ê C)ï46êïD)ïå
-
-
- ü
- êêêêèa∙(3b + c)
- êêêë =è5∙(3∙(-4) + (-5))
- êêêë =è5∙((-12) +(-5))
- êêêë =è5∙(-17)
- êêêë =è-85
-
- ÇïB
- 4
- #êèEvaluateïa∙(bì - cì) if a is "2", b is "-4", and c is "5".
-
-
- êïA)ï-6ê B)ï12êïC)ï-18êïD)ïå
-
-
- ü
- #êêêê a∙(bì - cì)
- #êêêè =è2∙((-4)ì - 5ì)
- êêêè =è2∙(16 - 25)
- êêêè =è2∙(16 + (-25))
- êêêè =è2∙(-9)
- êêêè =è-18
- ÇïC
- 5êê 3x - y
- #êêEvaluateï───────èif x is "4"ïand y is "-6".
- êêêè x + y
-
- êïA)ï23ê B)ï-9êïC)ï46êèD)ïå
-
-
- ü
-
- è3x - yê 3(4) - (-6)ê12-(-6)ê12 + 6ê18
- #è───────è=è───────────è=è───────è=è──────è=è──ï=ï-9
- è x + yêï4 + (-6)êè -2êë-2êï-2
-
-
- ÇïB
- 6
- #êêèEvaluateï3xì - 5x + 15ïif x is "-3".
-
-
- êïA)ï57ê B)ï-37ê C)ï42êèD)ïå
-
-
- ü
- #êêêê 3xì - 5x + 15
- #êêêè =è3(-3)ì - 5(-3) + 15
- êêêè =è3∙9 - 5(-3) + 15
- êêêè =è27 - (-15) + 15
- êêêè =è27 + 15 + 15
- êêêè =è57
- ÇïA
- 7
- êê Find "d" if d = r∙t , r is 40, and t is 2.
-
-
- êïA)ï60ê B)ï80êïC)ï50êèD)ïå
-
-
- ü
-
- êêêêèd = r∙t
- êêêêèd = (40)(2)
- êêêêèd = 80
-
-
- ÇïB
- 8
- êèFind "I" if I = P∙r∙t , P is $4,000, r is .06, and t is 10.
-
-
- ê A)ï$2,400ë B)ï$24ê C)ï$240êïD)ïå
-
-
- ü
- êêêêïI = P∙r∙t
-
- êêêêïI = (4,000)(.06)(10)
-
- êêêêïI = $2,400
-
- ÇïA
- 9êêë1
- #êïFind "A" ifèA =ï─∙(B + b)∙h,ïB is 14, b is 12ïand h is 4.
- êêêê2
-
- êïA)ï46ê B)ï24êïC)ï52êèD)ïå
-
-
- ü
- êêêëA = 1/2∙(B + b)∙h
- êêêëA = 1/2∙(14 + 12)∙4
- êêêëA = 1/2∙(26)∙4
- êêêëA = 13∙4
- êêêëA = 52
-
- ÇïC
- # 10êêè 2xì - 3x - 5
- #êêïEvaluateè ────────────èif x is "2".
- #êêêê xì + 4x + 6
-
- êïA)ï-1/6ë B)ï27êïC)ï33/12êD)ïå
-
-
- #üêï2xì - 3x - 5ê2(2)ì - 3(2) - 5ê2∙4 - 3∙2 - 5
- #êê ────────────è=è────────────────è=è─────────────
- #êêïxì + 4x + 6êï2ì + 4∙2 + 6êè 4 + 8 + 6
-
- êê 8 - 6 - 5ê2 - 5ê-3êè1
- #êè =è─────────è=è─────è=è──è=è- ──
- êêë18êë18ê 18êè6
- ÇïA
-
-