preg_match

(PHP 3>= 3.0.9, PHP 4 >= 4.0.0)

preg_match -- Perform a regular expression match

Description

int preg_match ( string pattern, string subject [, array matches])

Searches subject for a match to the regular expression given in pattern.

If matches is provided, then it is filled with the results of search. $matches[0] will contain the text that matched the full pattern, $matches[1] will have the text that matched the first captured parenthesized subpattern, and so on.

Returns TRUE if a match for pattern was found in the subject string, or FALSE if not match was found or an error occurred.

P°φklad 1. Find the string of text "php"

// the "i" after the pattern delimiter indicates a case-insensitive search
if (preg_match ("/php/i", "PHP is the web scripting language of choice.")) {
    print "A match was found.";
} else {
    print "A match was not found.";
}

P°φklad 2. find the word "web"

// the \b in the pattern indicates a word boundary, so only the distinct
// word "web" is matched, and not a word partial like "webbing" or "cobweb"
if (preg_match ("/\bweb\b/i", "PHP is the web scripting language of choice.")) {
    print "A match was found.";
} else {
    print "A match was not found.";
}
if (preg_match ("/\bweb\b/i", "PHP is the website scripting language of choice.")) {
    print "A match was found.";
} else {
    print "A match was not found.";
}

P°φklad 3. Getting the domain name out of a URL

// get host name from URL
preg_match("/^(http:\/\/)?([^\/]+)/i",
"http://www.php.net/index.html", $matches);
$host = $matches[2];
// get last two segments of host name
preg_match("/[^\.\/]+\.[^\.\/]+$/",$host,$matches);
echo "domain name is: ".$matches[0]."\n";

This example will produce:
domain name is: php.net

See also preg_match_all(), preg_replace(), and preg_split().