This example puts several Node objects in a TreeView control. The code checks to see if a Node has children nodes. If so, then it displays the text of the children nodes. To try the example, place a TreeView control on a form and paste the code into the form's Declarations section. Run the example, click a Node object to select it, then click the form to see the text of the Node object's children.
Option Explicit
Private Sub Form_Click()
Dim strC As String
Dim N As Integer
If TreeView1.SelectedItem.Children > 0 Then ' There are children.
' Get first child's text, and set N to its index value.
strC = TreeView1.SelectedItem.Child.Text & vbLF
N = TreeView1.SelectedItem.Child.Index
' While N is not the index of the child node's
' last sibling, get next sibling's text.
While N <> TreeView1.SelectedItem.Child.LastSibling.Index
strC = strC & TreeView1.Nodes(N).Next.Text & vbLF
' Reset N to next sibling's index.
N = TreeView1.Nodes(N).Next.Index
Wend
' Show results.
MsgBox "Children of " & TreeView1.SelectedItem.Text & _
" are: " & vbLF & strC
Else ' There are no children.
MsgBox TreeView1.SelectedItem.Text & " has no children"
End If
End Sub
Private Sub Form_Load()
TreeView1.BorderStyle = 1 ' Ensure border is visible
Dim nodX As Node
Set nodX = TreeView1.Nodes.Add(,,"d","Dates")
Set nodX = TreeView1.Nodes.Add("d",tvwChild,"d89","1989")
Set nodX = TreeView1.Nodes.Add("d",tvwChild,"d90","1990")
' Create children of 1989 node.
Set nodX = TreeView1.Nodes.Add("d89",tvwChild, ,"John")
Set nodX = TreeView1.Nodes.Add("d89",tvwChild, ,"Brent")
Set nodX = TreeView1.Nodes.Add("d89",tvwChild, ,"Eric")
Set nodX = TreeView1.Nodes.Add("d89",tvwChild, ,"Ian")
nodX.EnsureVisible ' Show all nodes.
' Create children of 1990 node.
Set nodX = TreeView1.Nodes.Add("d90",tvwChild, ,"Randy")
Set nodX = TreeView1.Nodes.Add("d90",tvwChild, ,"Ron")
nodX.EnsureVisible ' Show all nodes.
End Sub