Error 58              Illegal Character in Identifier                pp 323

 Source:  Compiler

 Cause:   Identifier must start with letter or underscore.

 Remedy:  Examine the statement ahead of the error cursor for the above
          condition.


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 Example:
       TYPE
          Days = (1,2,3,4)    ;  { Wrong   -  1st char is numeric    }
          Days = (_1,_2,_3,_4);  { Correct -  1st char is alpha or _ }

       VAR
          1Var : Integer;        { Wrong   -  1st char is numeric    }
          #Var : Integer;        { Wrong   -  1st char is numeric    }

       BEGIN
       END.